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1 Circuit Analysis For the circuit shown in Figure 1, find the current through and the potential difference across each resis

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162 322 VN 14 N I VI Ig 4u lav Z 48r. - Vgcov → Appeying KCL at Node - N ie EI = 0 It Ig+ 13 + 19 = 0 V-12 + VY f + VN 3 4 nI or Ig 9.6 To Tor 0.cn » potenpal difference 3r I, X3n = 0.8x3= 2.4v Vana I X4 u = 624x4= 9.6 V = 9.6V VG & Iz x 48 = 0.2448

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