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18-10 A common method of making coaxial lines is to use a very thin outer conductor,...
This coaxial cable consists of a solid inner conductor of radius ?1 and a very thin...
This coaxial cable consists of a solid inner conductor of radius ?1 and a very thin outer conductor of radius ?2. The two cables carry equal currents ?, but in the opposite direction. The current density is uniformly distributed within each conductor. a) Find expressions for the magnetic field (B-field) in three regions: i) within the inner conductor ii) in the space between the conductors iii) outside the outer conductor. b) Draw a graph of B vrsus the cylindrical radius...
Self-Inductance of a Coaxial Cable
Intro: A coaxial cable consists of alternating coaxial cylinders ofconducting and insulating material. Coaxial cabling is the primarytype of cabling used by the cabletelevision industry and is alsowidely used for computer networks such as Ethernet, on account ofits superior ability to transmit large volumes of electrical signalwithminimum distortion. Like all other kinds of cables, however,coaxial cables also have some self-inductance that has undesirableeffects, such as producing somedistortion and heating.Consider a long coaxial cable made of two coaxial cylindricalconductors that carry...
The coaxial cable shown in the figure consists of a solid inner conductor of radius r...
The coaxial cable shown in the figure consists of a solid inner conductor of radius r 1 and a thin hollow outer conductor of radius r 2. The two conductors carry equal but opposite currents I, uniformly distributed. Find expressions for the strength of the B-field as a function of radial position r for a. Osrsri b.risrsrz c. r>r2 Inner conductor radius rı - - --- - - - ----- - Outer conductor
Problem 2 (15 points): Consider the coaxial arrangement of two very long, thin hollow conductors shown in the figure. Assume that a constant current / flows in one direction on the inner conductor, a...
Problem 2 (15 points): Consider the coaxial arrangement of two very long, thin hollow conductors shown in the figure. Assume that a constant current / flows in one direction on the inner conductor, and a constant current 31 (i.e. three times the current) flows in the opposite direction on the outer conductor. Can one use Ampere's Law to find the magnetic field at any point due to this configuration of currents, or should one use the Biot-Savart Law? Please explain....
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...
The coaxial cable shown in the figure consists of a solid inner conductor of radius r 1 and a thin hollow outer conductor of radius r 2. The two conductors carry equal but opposite currents I, uniformly distributed. Find expressions for the strength of the B-field as a function of radial position r for a. Osrsri b.risrsrz c. r>r2 Inner conductor radius rı - - --- - - - ----- - Outer conductor
Problem 2 (15 points): Consider the coaxial arrangement of two very long, thin hollow conductors shown in the figure. Assume that a constant current / flows in one direction on the inner conductor, and a constant current 31 (i.e. three times the current) flows in the opposite direction on the outer conductor. Can one use Ampere's Law to find the magnetic field at any point due to this configuration of currents, or should one use the Biot-Savart Law? Please explain....
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...
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