Question

For the following design C1-0.05F L1-2H R2-40 R1 40 C2-0.05F L2-2H Va-4cos(10t+900)V Vb-4cos(10t+90°] R4-40 L3 0.1H C3-0.1F R3-40Q 1R6-20 vc=4cos( 20t+900)V vd:4cos( 10t+600)V (Remember that i) ω is given in rad/sec, i) the above circuits have different Impedances for different frequencies, ii) we replace the shorted voltage power supplies with a short circuit, İV) with a+jb the rectangular form and NO the polar form we have a-Acos(9), b-Asin(8), A- vatb2 , θ tan-1 (a) , θ-1800 ( a) ifa < 0) ifa >0 -tan"1

I'm unsure how to work this problem. Please include all drawings where necessary.

Answer 1