Question

For the following design L1-2H C1-0.05F R1.4Ω R2-4Ω C2-0.05P L2-2H Va 4cos(10t+90°)V vb-4cos( 10t+90"N R4-4Ω R6:2Ω RS-4Ω Vc-4cos(20t+90jv vds4cos( 10t+60ον (Remember that i) w is given in rad/sec, ii) the above circuits have different Impedances for different frequencies, ii) we replace the shorted voltage power supplies with a short circuit, iV) with atjb the rectangular form and Ad the polar form we have a-Acos(8), b-Asin(θ), A-: va2+1,7 , θ= tan-l (4)if a > 0, θ= 180-tan-IL) if a <0)

Answer 1

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