1.If a locus is in Hardy Weinberg proportions, it means that the sum of its allelic frequencies is 1.we consider a locus with two alleles p and q .therefore at hardy Weinberg equilibrium, p+q=1 and also the sum of genotype frequencies is one, p^2 +2pq+ q^2=1
2.Yes
3.It is because being in hardy Weinberg proportions has to do with alleles involved with a single locus for example- A and a are the two alleles of a single locus with allelic frequencies p and q respectively. If this locus is in hardy Weinberg equilibrium that means p+q=1 and has nothing to do with another locus.
And B and b are another two alleles of another locus.
test. Use the Chi-square table provided by the TA. In the lab write-up answer these questions:...
A
corn genetics lab.
i got total chi-square of 14.34. And the number of degrees of
freedom of 1.
How can I find the probability of a Match base on the table?
please explain.
Degree of Freedom 0.99 0.000 0.020 0.115 0.297 0.554 0.872 1.239 1.647 2.088 2.558 3.053 3.571 4.107 4.660 5.229 5.812 6.408 7.015 7.633 8.260 9.542 10.856 12.198 13.565 14.953 22.164 Probability of Exceeding the Critical Value 0.95 0.90 0.75 0.50 0.25 0 .10 0.0040.016 0.1020.455 1.32...