An electric field of 1.92 kV/m and a magnetic field of 0.493 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed?
Given that
electric field E=1.92*10^3 V/m
magnetic field B=0.493 t
basing on the concept of electro magnetic waves
now we find the electron speed
th electrons speed V=E/B=1.92*10^3/0.493=3.895*10^3 m/s
An electric field of 1.92 kV/m and a magnetic field of 0.493 T act on a...
Chapter 28, Problem 008 An electric field of 1.86 kV/m and a magnetic field of 0.305 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed? Number Units the tolerance is +/-7% SHOW HINT
An electric field of 2.24 kV/m and a magnetic field of 0.383 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed?
5) An electric field of 2.05 KV/m and a magnetic field of 0.354 T acts on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed? - 20 pt
.In a particle accelerator there is a magnetic field and an electric field perpendicular to each other. A charged particle traverses the area where both fields meet without deviating from its path. The magnitude of the magnetic field is 0.500 T and the electric field has a magnitude of 2.5 kV / m. Find the speed of the particle.
Crossed electric and magnetic fields are established over a certain region. The magnetic field is 0.6000 T vertically downward. The electric field is 2.000 x 106 V/m horizontally east. An electron, traveling horizontally northward, experiences zero resultant force from these fields and so continues in a straight line. What is the electron's speed? m/s
A uniform electric field of magnitude 148 kV/m is directed upward in a region of space. A uniform magnetic field of magnitude 0.42 T perpendicular to the electric field also exists in this region. A beam of positively charged particles travels into the region. Determine the speed of the particles at which they will not be deflected by the crossed electric and magnetic fields. (Assume the beam of particles travels perpendicularly to both fields.) m/s
A magnetic field has a magnitude of 0.0010 T, and an electric field has a magnitude of 6.1 × 103 N/C. Both fields point in the same direction. A positive 2.4-μC charge moves at a speed of 2.4 × 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge.
A magnetic field has a magnitude of 1.20 10-3 T, and an electric field has a magnitude of 5.70 103 N/C. Both fields point in the same direction. A positive 1.8-µC charge moves at a speed of 3.40 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge.
A beam of electrons is accelerated through a potential difference of 10 kV before entering a region having uniform electric and magnetic fields that are perpendicular to each other and perpendicular to the direction in which the electron is moving. If the magnetic field in this region has a value of 0.010 T, what magnitude of the electric field is required if the particles are to be undeflected as they pass through the region?
An electron moves with speed 5.0 times 10^5m/s in a uniform magnetic field of strength 0.60 T that points Hast. At some instant, the electron experiences an upward magnetic force of magnitude 4.0 times 10^14 N. In what direction is the electron moving at that instant? [If there is more than one possible direction, describe all the possibilities.] On a carefully drawn and labeled diagram, show the (possible) direction(s) of the electron's velocity relative to the magnetic field and the...