Question

2. Suppose vitamin D levels among adults 20 and older in the U.S has a Normal distribution with population mean 60 µmol/L and a population standard deviation of 25 µmol/L.

1. What is the probability that a sample mean of 25 randomly selected people is less than 30 µmol/L (assume population standard deviation is 30 µmol/L).

Answer 1

rey sample size = 25 (P) population Mead = Go Mmol/L (and population standard devitray = 25 mmol/ Z = T-M Plă < 30 pmol/) * To find this Garent ñ to Z. z= 30-60 = -5 30 So male teed p (2-2-5) = 0.0002