Question

1. The following represents a binomial experiment. Suppose that 42% of all college students smoke cigarettes.  A sample of 26 is selected randomly.  What is the probability that 12 students smoke?

1. 0.142
2. 10.92
3. 0.420
4. 0.462

Answer 1

We have here,

$X\sim Binomial(n=26,p=0.42)$

P[X=12]

$=C(26,12)*(0.42)^{12}*(1-0.42)^{14}$

=0.142

A ) 0.142