please help
An HCl solution has a pH = 4. If you dilute 10 mL of the solution to 100mL, the final pH will be:
SInce we know that
[H+] for 10 ml = 10-4 = 0.0001 = M1
now we know that from dilution law
M1V1 = M2V2
or M2 = 0.0001*10 / 100= 0.00001
now
pH of diluted solution = -log[0.00001] = 5
the final pH will be 5
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