Question

JAVA Hi I would like assistance on this: One of the input is below and I keep getting ASCENDING instead of UNSORTED:

11 2009 153333

3 ZIPS, What Order?: Write a program named ZipOrder that the reads in three zip codes from standard input and prints to standard output one of three words: "ASCENDING","DESCENDING","UNSORTED". The zip codes are guaranteed to be distinct from each other. In particular: if each zip code read in is greater than to the previous one, "ASCENDING" is printed. if each zip code read in is less than to the previous one, "DESCENDING" is printed. otherwise, "UNSORTED" is printed. The program accomplishes this by reading the zip codes and passing them as arguments to a method named direction. This method returns a string ("ASCENDING", "DESCENDING", or "UNSORTED") that the program prints out. The function carries out the zip code order logic. CONSTRAINT: You must define and use the method direction ♡ Interactive Session Visible newlines Visible whitespace Display stdin Display stdout 1 2 3 ASCENDING

Answer 1

Answer:

Explanation:

Here is the code which has the method direction taking 3 zip codes.

If zip1 < zip2 < zip3, it returns ascending

If zip1 > zip2 > zip3 it returns descending

Otherwise, it returns unsorted.

feel free to comment if you need any help!

Code:

import java.util.Scanner;
public class Main
{
public static String direction(int zip1, int zip2, int zip3)
{
if(zip2 > zip1 && zip3>zip2)
return "ASCENDING";
else if(zip2<zip1 && zip3<zip2)
return "DESCENDING";
else
return "UNSORTED";
}
   public static void main(String[] args) {
      
       Scanner sc = new Scanner(System.in);
      
       int zip1 = sc.nextInt();
       int zip2 = sc.nextInt();
       int zip3 = sc.nextInt();
      
       System.out.println(direction(zip1, zip2, zip3));
      
   }
}

Output:

3 5 4 UNSORTED ...Program finished with exit code 0 Press ENTER to exit console.

PLEASE UPVOTE IF YOU FOUND THIS HELPFUL!

PLEASE COMMENT IF YOU NEED ANY HELP!