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Answer #1

a)
Since we know the population standard deviation, the appropriate test statistic is,
z test statistic

b)
Population - US Students
Sample - Sample of Idaho Students

c)
H0: \mu = 498

H1: \mu > 498

For \alpha = 0.05, critical value of test statistic, z is 1.645

Standard error of mean = \sigma / n = 97 / LO = 4.027706

Test statistic = (515 - 498) / 4.027706 = 4.22

Since the observed test statistic is greater than the critical value, Reject the null hypothesis

d)

Margin of error = Critical z * Std error = 1.645 * 4.027706 = 6.625576

95% CI of the true mean is,

(515 - 6.625576, 515 + 6.625576)

(508.3744,  521.6256)

e)

d = |x -\mu |/ \sigma = |515 - 498| / 97 = 0.1753

Since d is less than 0.2, the magnitude is small.

r2 = na

f)

Students from Idaho had significantly higher math SAT scores than the nation.

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