Question

Resource Deployment Questions Problem? An agency has determined that it needs to field an average of 63 units per day to cover three 8- hour shifts. The agency wishes to allocate their units based on the h ard score for all patrol activities on each shift. Given the following information, how many units should be assigned to ca chu Hazard Weight PAS Part I Crimes Part II Crimes All Other PA Shift Hazard 1.242 Shini Hazard PA Score 4.986 625 15.457 26,66% Part I Crimes Part Il Crimes All Other PA Total 312 9116 13,136 21.360 SHIFT III HAZARD WEIGHT PA SHIFTI HAZARD SCORE SHUFT II HAZARD PA SCORE PA HAZARD SCORE Part I 1.242 2,541 4.986 Part 1 2.558 6,332 6,225 Other 9,336 TOTAL HAZARD 12,487 15.457 TOTAL helen) SI TIVAD TOTAL HVAD NUMBER OF UNITS ON SUNT ROUNDED NUMER OF SHIFT SHIFT SHIFT III TOTALN SANITY CHECK: DOES Nu Shift - Nu Shift II - Nu Shift lll - Total Nu in the beginning? (nr de the mark)

Answer 1

Hazard Score=Hazard Weight*PA

		Shift I		Shift II		Shift III		Totol Hazard Score
	Hazard weight	PA	Hazard Score	PA	Hazard Score	PA	Hazard Score
Part I Crimes	6	1242	=6*1242 =7452	2541	=6*2541 =15246	4986	=6*4986 =29916
Part II Crimes	5	2558	=5*2558 =12790	6332	=5*6332 =31660	6225	=5*6225 =31125
All Other PA	1	9336	=1*9336 =9336	12487	=1*12487 =12487	15457	=1*15457 =15457
Total			29578		59393		76498	165469

	Shift Hazard Score	Total Hazard Score	Number of units on shift	Rounded number of unites on shift
Shift I	29578	165469	=29578/165469*63 =11.26	11 units
Shift II	59393	165469	=59393/165469*63 =22.61	23 units
Shift III	76498	165469	=76498/165469*63 =29.13	29 units
		Total Nu		63 Units

Sanity Check:

Shift I Nu +Shift II Nu+ Shift III Nu = Total Nu in the beginning

11+23+29 =63 Units