lf you wish to estimate a population mean with a sampling distribution error SE: 026 using...

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Answer 1

Answer #1

solution:

standard error= $\sigma /sqrt(n))$

SE=0.26

squariong on bothisded

sigma^2/n=0.26^2

but sigma^2=3.7 given

3.7/0.26^2=n

54.7=n

n=55

Sample size=55

ANSWER:55

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Answer 2

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