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The figure shows a graph of electric potential V (in Volts) versus position x (in cm). If a proton (m = 1.67 x 10-27 kg, q =

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we know t = -duces dx Ez-(0-30), +30=30 NC (2-1) cm 102 $0 Q: 1:25 = .681619x30 m2 - m m 1,67810 27X102 a=280748108tm/A² a: 2Please UpVote and let me know if you face any problem, confusion or see any error.
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