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Q 1. An op amp with an open-loop gain of 6 x 105 and Vcc = 10V has an output voltage of 3 V. If the voltage at the inverting

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Ao 6x15 vozov, r=-luv rt_2 for op Ame rozton. [ut-w- 3= 6x20 [ut (14)] 3 = 0.6 lut +] Niti z 5 Tuta 4 uvN+ 34 4kn g2=3ku f = 75mw I given] Shame Vo 7573 No=155 vt - 3V Vox Retakw But Mence 37 = 4 futro tro, + 4 3 15 x 4 R2+4 fitI tUm is MA ZOV Kchet ist V. ZO Rif voz-kits]. But ; norzo vo 22 R2 L. RL= - RIUS i ts & 9 ľ=-15, R2=12kw But then - 15 = R160 = 36, +42-563-8 V4 Anresting Any inverting Men Rf N vz R2 - fut ht f3 R Re ollo M 43 shf von het ht toku one. Resistancedo2= 23 va 24 Nor = Rt 13 R3 2 from A3 Von & Rit REVO hftRt NO2 Rf RITRE Noit vo vor Noz voz von using O and 2 N3 74 24 Noz f③ and we compare get, Re - 3 R = R = 40 kn ft fz - 2D Rzz ff to = loku 4 fit ²5 = R3= R + R3 - 40 = 8kn क For 4= Rt- 4o-ska 2

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