Write a function in Python that solves the linear system ??=? using Gaussian Elimination, taking ?,? as input. The function should have two phases: the elimination phase, and the back substitution phase. You can use numpy library.
The solution to the above problem is:-
import numpy as np
def f_elimination(A, b, n):
"""
Here we are calculating the forward part of Gaussian
elimination.
"""
for row in range(0, n-1):
for i in range(row+1, n):
factor = A[i,row] / A[row,row]
for j in range(row, n):
A[i,j] = A[i,j] - factor * A[row,j]
b[i] = b[i] - factor * b[row]
print('A = \n%s and b = %s' % (A,b))
return A, b
def back_substitute(a, b, n):
""""
Here we are doing back substitution, returns the Gauss
result.
"""
x = np.zeros((n,1))
x[n-1] = b[n-1] / a[n-1, n-1]
for row in range(n-2, -1, -1):
sum = b[row]
for j in range(row+1, n):
sum = sum - a[row,j] * x[j]
x[row] = sum / a[row,row]
return x
def gaus(A, b):
"""
This function performs Gauss elimination without pivoting.
"""
n = A.shape[0]
# Check for zero diagonal elements
if any(np.diag(A)==0):
raise ZeroDivisionError(('Division by zero will occur; '
'pivoting currently not supported'))
A, b = f_elimination(A, b, n) # calling f_elimination and
storing the result in A,b.
return back_substitute(A, b, n) # Here we are returning the
back_substitute result.
# Main program starts here
if __name__ == '__main__':
A = np.array([[9, 3, 5],
[4, -3, -24, ],
[1, 4, -4, ]])
b = np.array([0, 4, 2])
x = gaus(A, b) # calling guassian function and storing the above
result in x.
print('Gauss result is x = \n %s' % x)
The output for the above code is:-
Thank you.
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