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In a sample of 15 marijuana users, the mean number of prior emergency room admissions was...

In a sample of 15 marijuana users, the mean number of prior emergency room admissions was 2.4 with a standard deviation of 0.8. Construct a 90% confidence interval for the population mean number of emergency room admissions and interpret your results.

math   Statistics-And-Probability   
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Answer #1

Confidence Interval
ar{X} pm t_{alpha /2, n-1} S/sqrt{n}
/2,n-1to.1/2,15-1- 1.761
2.4 t 0.1/2.15-1 * 0.8/v/15
Lower Limit = 2.4 -t 0.1/21 5-10.8/V15
Lower Limit = 2.0362
Upper Limit = 2.4+t0.1/2.1 5-10.8/V15
Upper Limit = 2.7638
90% Confidence interval is ( 2.0362 , 2.7638 )

Population mean  mu lies in the interval  ( 2.0362 , 2.7638 )

Interpretation :- If repeated samples are drawn and confidence interval is calculated, then 90% of the population mean lies in the interval  ( 2.0362 , 2.7638 ) .

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