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AM You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% con
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Answer #1

a)

We know that the 90% confidence interval for population mean is given by:

\\(\overline{x}\pm Z_{0.10/2}\frac{\sigma}{\sqrt{n}})\\ \\ (\overline{x}\pm Z_{0.05}\frac{\sigma}{\sqrt{n}})\\ \\ (144\pm (1.645)\frac{15.60}{\sqrt{35}})\\ \\ (144\pm 4.34)\\ \\ (139.66,148.34)

b)

We know that the 95% confidence interval for population mean is given by:

\\(\overline{x}\pm Z_{0.05/2}\frac{\sigma}{\sqrt{n}})\\ \\ (\overline{x}\pm Z_{0.025}\frac{\sigma}{\sqrt{n}})\\ \\ (144\pm (1.96)\frac{15.60}{\sqrt{35}})\\ \\ (144\pm 5.17)\\ \\ (138.83,149.17)

c)

So, with 90% confidence, it can be said that the population mean lies in 1st interval and with 95% confidence, it can be said that the population mean lies in 2nd interval. Also, 95% interval is wider than 90% interval.

Hence option A.

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