Question

Suppose that the position of a particle is given by 8 = f(t) = 6t3 + 7t + 9. (a) Find the velocity at time t. т v(t) = S (b)
Find the derivative of f(x) = –67 + 10 23 Type your answer without fractional or negative exponents. Use sqrt(x) for V. f(x)
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Answer #1

Soj s= 6+²+7t +9 ca) Velocity SP =(77A 7P 16+7t + 279) 7P 6X3+²+7 to 18+²+7 Im Ans s (6) Velocity at time t = 3 sec = (2) 180f(x) = -6.X + lo 23 diff. wir to a f(x) = -6 d x da + lod (x-3 da = - 6 X 1 2.5x + lo (-37) f(x) = - 3 Jx 30 Ans. x 4

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