Question

A beam of mass 100.0 kg and length 4.56789 m is supported by a cable as shown below. There is a mass,
M = 20.00 kg, hanging from the beam at one end. The beam is at rest. Calculate the tension in the cable.

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Answer #1

Taking moment about pivot point,

Mg(l cos25) + mg(0.5 l cos25) - T(l sin25) = 0

T = g cos25(M + m/2)/ sin25

T = (9.8 cos25) [20 + 100/2]/sin(25) = 1471.13 N

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