A buffer solution is composed of 0.380 M HA, a weak
monoprotic acid, and 0.760 M NaA, the sodium salt of the
acid. The solution has a pH of 4.10. What is the
Ka of the weak acid, HA?
tks!!!!!!!!!!!!!
use the Handerson equation find the pKa first from that find the Ka value
pH = pKa + log(NaA/HA)
pH is given = 4.10
NaA = 0.76 M,, HA = 0.38
put all these in the above equation
4.10 = pKa + log(0.76/0.38)
pKa = 4.10-0.3010
pKa = 3.8
now use the formula
ka = 10-pKa
Ka = 10-3.8
Ka = 1.58 x 10-4
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