ANSWER:
we know that,
pH = -log[H+]
[H+][OH-] = 10-14
For solution A:
[H+] = 0.00055 M
pH = - log[H+]
pH = -log(0.00055)
pH= 3.26
[H+][OH-] = 10-14
(0.00055 M)[OH-] = 10-14
[OH-] = 1.82 x 10-11 M
For solution B:
[OH-] = 0.0045 M
[H+][OH-] = 10-14
[H+](0.0045 M) = 10-14
[H+] = 2.22 x 10-12 M
pH = -log[H+]
pH = -log(2.22 x 10-12 M)
pH = 11.65
For solution C:
pH = 7.49
pH = -log[H+]
7.49 = -log[H+]
[H+] = 3.24 x 10-8 M
[H+][OH-] = 10-14
(3.24 x 10-8 M)[OH-] = 10-14
[OH-] = 3.09 x 10-7 M
[H+] | [OH-] | pH | |
Solution A | 0.00055 M | 1.82 x 10-11 M | 3.26 |
Solution B | 2.22 x 10-12 M | 0.0045 M | 11.65 |
Solution C | 3.24 x 10-8 M | 3.09 x 10-7 M | 7.49 |
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