Solution A :
[H+] = 6.4 x 10-8 M
[OH-] = (10-14) / (6.4 x 10-8)
= 1.56 x 10-7 M
pH = -log [H+]
= -log (6.4 x 10-8)
= 7.19
pOH = 14 - pH
= 14 - 7.19
= 6.81
Solution B :
[H+] = (10-14) / [OH-]
= (10-14) / (0.00040)
= 3.0 x 10-11 M
[OH-] = 0.00040 M
pH = -log [H+]
= -log (3.0 x 10-11)
= 10.5
pOH = 14 - pH
14 - 10.5
= 3.5
Solution C :
[H+] = 10-pH
= 10-13.48
= 3.31 x 10-14 M
[OH-] = (10-14) / (3.31 x 10-14)
= 3.0 x 10-1
pH = 13.48
pOH = 14 - pH
= 14 - 13.48
= 0.52
Solution D :
[H+] = (10-14) / pH
= 10-14 / (1.5 x 10-10)
= 6.67 x 10-5M
[OH-] = 10-pOH
= 10-9.82
= 1.5 x 10-10 M
pH = 14 - pOH
= 14 - 9.82
= 4.18
pOH = 9.82
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