Question

TA 1 66 lb 32°N 9114/210/2870 TA 2 23 48 lb 2516 4 23/35/1a) 26 30 11 7 2017 TA 3 67 lb 23 11 be/22/5A/zel 02 28193118 8/21/62 SZOLL 12100 29€) PZI & SKVE TA 4 69 lb Four illustrious TA's are pushing on a 41 pound, 4.9 ft radius roulette wheel. Counterclockwise is positive.

Answer 1

Here we apply definition of torque and Newton's law of rotation.

낀 A We know, Torque ? = 8& F Due to TAI Ratius, T=4.9 ff. E T = (TAI) (8) Ceas 320 320 C clockwise - T, = (66 lb) (4.9 ft) (as 32° (clockwue) T = 274.26 lb-ft I clockwue B) - TAZ T2 = (Taz) (2) Sinio (clockwire) C 6110 T = (1816) (4.9 ft) Sin 110 Direction is given by right kand rule z = 44.88 lb-ft (counter clock wire) wise X. - T3 = (TA) (a) Singo (counter clock) - 73 = 67-1b)(4-944) z = 328.3 lb-ft counter clock were (d) Here fr i o=0° Tx=( Tag (v) siroo =0 (E) Tnet - (T3 - T, -(z) counter clock wille - (308.3-274.26-44.8) lbf4 = 9.16 lb-ft (counter cloch wise)

2 Tnet = Ian 2 = 1 Mr? 9.16.lt=5&p=3(41)(4.9) Zeb@H?« > (9.16) (32-2)(sec 3 = (492-205) a= 0.5992 ras/sec2 counter clockwice.