Question

5) Consider the following torque balance : H Td Luo Girm & M= 1 kg , Ig : 1A , d = 1M , M = 4x X 10 (f/m), g= 10 m/s2 , L=1m

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Answer #1

I am assuming that the pivotal point is in the middle of the balance

suppose I_2 current wire applies the force = F on the I1 wire so by torque balance

Στ = 0 about the pivotal point

F*L/2 = Mg * L/2

F =Mg

F = magnetic force by wire 2 on wire 1

= I1 *L*B2 = I1 *L*μ*I2 / 2*pi*d

I1 *L*μ*I2 / 2*pi*d = Mg

1*1*(4pi*10^-7)*I2 / ( 2*pi*1) = 1*10

from here  I2 =

TUL 41 Iz =1x10 1x 107 21x1 Result: 12 5 000 000 = 10 Alternate forms: 12 = 50 000 000

I2 = 5*107 A answer ( unbelievably high current )

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Goodluck Comment in case any doubt, will reply for sure..

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