Kb of triethylamine is 5.2 x 10^-4
Pkb = -log kb = 3.28 ~ 3.3
A 21.1 mL sample of 0.233 M triethylamine, (C,H3)2N, is titrated with 0.349 M nitric acid....
A 29.9 mL sample of 0.363 M triethylamine, (C2H3)3N, is titrated with 0.307 M nitric acid. The pH before the addition of any nitric acid is Use the Tables link in the References for any equilibrium constants that are required. A 23.7 mL sample of 0.252 M diethylamine, (C2H3)2NH, is titrated with 0.349 M hydrobromic acid. At the titration midpoint, the pH is Use the Tables link in the References for any equilibrium constants that are required.
A 25.9 mL sample of 0.207 M trimethylamine, (CH3)2N, is titrated with 0.223 M nitric acid After adding 8.44 mL of nitric acid, the pH is Use the Tables link in the References for any equilibrium constants that are required. A 22.3 mL sample of 0.369 M diethylamine, (CH3)2NH, is titrated with 0.218 M nitric acid. The pH before the addition of any nitric acid is Use the Tables link in the References for any equilibrium constants that are required.
A 21.2 mL sample of 0.231 M triethylamine, (C2H5)3N, is titrated with 0.232 M hydrochloric acid. After adding 31.0 mL of hydrochloric acid, the pH is Use the Tables link in the References for any equilibrium constants that are required. Submit Answer Retry Entire Group 9 more group attempts remaining A 28.3 mL sample of 0.358 M ethylamine, C2H5NH2, is titrated with 0.233 M hydrobromic acid. After adding 19.4 mL of hydrobromic acid, the pH is Use the Tables link...
A 27.3 mL sample of 0.355 M triethylamine, (C2H5)3N, is titrated with 0.355 M hydrochloric acid. After adding 38.2 mL of hydrochloric acid, the pH is Use the Tables link in the References for any equilibrium constants that are required. A 22.8 mL sample of 0.300 M methylamine, CH3NH2, is titrated with 0.315 M hydrochloric acid. The pH before the addition of any hydrochloric acid is Use the Tables link in the References for any equilibrium constants that are required.
A 28.7 mL sample of 0.383 M ethylamine, C2H5NH2, is titrated with 0.213 M nitric acid. After adding 21.5 mL of nitric acid, the pH is . Use the Tables link in the References for any equilibrium constants that are required.
A 24.1 mL sample of 0.215 M ethylamine, C2H5NH2, is titrated with 0.363 M nitric acid The pH before the addition of any nitric acid is required Use the Tables link in the References for any equilibrium constants that are A 24.1 mL sample of 0.215 M ethylamine, C2H5NH2, is titrated with 0.363 M nitric acid The pH before the addition of any nitric acid is required Use the Tables link in the References for any equilibrium constants that are
A 25.0 mL sample of 0.203 M ethylamine, C2H^NH2, is titrated with 0.225 M nitric acid. Before the addition of any nitric acid, the pH is (2) After adding 8.62 mL of nitric acid, the pH is (3) At the titration midpoint, the pH is (4) At the equivalence point, the pH is (5) After adding 35.4 mL of nitric acid, the pH is Use the Tables link on the toolbar for any equilibrium constants that are required. Not submitted...
A 21.2 ml sample of 0.217 M ethylamine, CH_NH, is titrated with 0.287 M nitric acid. After adding 24.0 mL of nitric acid, the pH is Use the Tables link in the References for any equilibrium constants that are required. Submit Answer Retry Entire Group 4 more group attempts remaining
1. A 24.9 mL sample of 0.332 M methylamine, CH3NH2, is titrated with 0.264 M perchloric acid. At the titration midpoint, the pH is . Use the Tables link in the References for any equilibrium constants that are required. 2. A 20.3 mL sample of 0.278 M methylamine, CH3NH2, is titrated with 0.224 M hydroiodic acid. The pH before the addition of any hydroiodic acid is . Use the Tables link in the References for any equilibrium constants that are...
A 27.4 mL sample of 0.307 M triethylamine, (C2H3)3N, is titrated with 0.265 M hydroiodic acid. After adding 12.7 mL of hydroiodic acid, the pH is Use the Tables link in the References for any equilibrium constants that are required. Submit Answer Try Another Version 3 item attempts remaining Write the net ionic equation for the acid-base hydrolysis equilibrium that is established when ammonium bromide is dissolved in water. (Use H2O instead of H.) + H2O(l) = + This solution...