5 )
E = kQ/R^2
if distance = R/2
E' = 4Qk/R^2 = 4E
if we double the charge and half the distance
E' = 8E
double the charge Q
E' = 2E ( C option )
part 6 )
W = pdv
at constant volume W = 0
W = 0 + 2po(4vo-vo) + 0 + po(vo-4vo)
W = 6povo - 3povo = 3povo ( D option )
5) B-Ch 19 (2 pts) The electric field at point Pdue to a point charge a...
15. Point P and point charge Q are separated by a distance R. The electric field at point Phas magnitude E. How could the magnitude of the electric field at point P be doubled to 25? O double the distance to 2R O reduce the distance to R2 reduce the distance to R/4 reduce the point charge to Q2 double the point charge to 20 11. What is the electric field strength atx-0 m, y-0 m produced by two electrons,...
At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 360 N/C. At a distance r2 from the charge, the field has a magnitude of 160 N/C. Find the ratio r2/r1.
**Please answer ALL parts. Thanks A point charge gives rise to an electric field with magnitude 4 N/C at a distance of 6 m. If the distance is increased to 24 m, then what will be the new magnitude of the electric field? N/C Submit Answer Tries 0/2 Point charges of 54 Q are placed at each corner of an equilateral triangle, which has sides of length 6 L. What is the magnitude of the electric field at the mid-point...
1. A particle with a charge of +4.20 nC is in a uniform electric field E⃗ directed to the negative x direction. It is released from rest, and after it has moved 6.00 cm , its kinetic energy is found to be 1.50×10−6 J . a. What work was done by the electric force? b. What was the change in electric potential over the distance that the charge moved? c. What is the magnitude of E? d. What was the change...
11:45イ adpoly.ankabut.ac.ae A flat disk 1.0 m in diameter is oriented so that the plane of the disk make an angle of s radians with a uniform electric field. If the field strength is BONC find the electric flux through the surface. A) 160m Nnm2/C #2500" Nm 2/C O 미 90m Nm2/C Question 3 (1 point) 0-50 +-40. E-2x10 N/C Electric field lines pass through a cube as shown in the diagram above. What is the electric flux through sides...
Electric Field from Arc of Ch A total charge Q-4.3 C is distributed uniformly over a quarter circle arc of radius a 6 cm as shown. 1) what is λ the linear charge density along the arc C/m Submit 2) What is E,, the value of the x-component of the electric field at the origin (k.n- 0.0) 3) What is E, the value of the y component of the electric field at the origin toy) (0.0)2 N/C Suhmit 3) What...
A point charge gives rise to an electric field with magnitude 4 N/C at a distance of 1 m. If the distance is increased to 2 m, then what will be the new magnitude of the electric field?
Basic Coulomb's law tells us that the electric field of a point charge q, E=ke q/r2, scales with distance r as 1/r2: when the distance increases by a factor of 2, the magnitude of the field decreases by a factor of 4. We can write this as E(r) ∝ 1/r2. An interesting and practically important question is how the electric field of a group of charges scales with distance (asymptotically) far away from the group. The figure below depicts 3...
23.28:At a certain distance from a point charge, the potential and electric field magnitude due to that charge are 4.98 V and 12.0 V/m, respectively. (Take the potential to be zero at infinity.) 1.What is the distance to the point charge? (d= ? m) 2.What is the magnitude of the charge? (q= ? c)
2. Electric field a) (5 pts) Which direction will a proton (charge = 1.6 x 10-19 C) move if it is released from points C, D, and E shown in the figure below? Draw an arrow at each of the points. At which of these points the electron will have maximum acceleration (magnitude)? с 6 cm 450 45° - 10 με 12 cm + 10 uc 6 cm 6 cm E B D A Page 1 of 3