Question

1. A particle with a charge of +4.20 nC is in a uniform electric field E⃗  directed to the negative x direction. It is released from rest, and after it has moved 6.00 cm , its kinetic energy is found to be 1.50×10⁻⁶ J . a. What work was done by the electric force? b. What was the change in electric potential over the distance that the charge moved? c. What is the magnitude of E? d. What was the change in potential energy of the charge?

2. A uniform electric field has magnitude E and is directed in the negative x direction. The potential difference between point a (at x= 0.70 m ) and point b (at x= 0.95 m ) is 300 V . a. Calculate the value of E. b. A negative point charge q=−0.200μC is moved from b to a. Calculate the work done on the point charge by the electric field.

3. A +2.30 μC point charge is sitting at the origin. a. What is the radial distance between the 500 V equipotential surface and the 1000 V surface? b. What is the distance between the 1000 V surface and the 1500 V surface?

4. The plates of a parallel-plate capacitor have a separation of 3.40 mm , and each has an area of 13.8 cm2 . Each plate carries a charge of magnitude 8.00×10⁻⁸ C . The plates are in vacuum. a. What is the capacitance? b. What is the potential difference between the plates? c. What is the magnitude of the electric field between the plates?

Answer 1