A particle with a charge of +4.20 nC is in a uniform electric field È directed in the negative x direction. It is released from rest, and after it has moved 6.00 cm, its kinetic energy is found to be + 1.50 × 10-6 J. (a) what work was done by the electric force? (b) What was the change in electric potential over the distance that the charge moved? (c) What is the magnitude of E? (d) What was the change in potential energy of the charge?
a)
Work done by the electric force
b)
Since
c)
ELectric field
d)
change in potential energy is
A particle with a charge of +4.20 nC is in a uniform electric field È directed in the negative x direction.
1. A particle with a charge of +4.20 nC is in a uniform electric field E⃗ directed to the negative x direction. It is released from rest, and after it has moved 6.00 cm , its kinetic energy is found to be 1.50×10−6 J . a. What work was done by the electric force? b. What was the change in electric potential over the distance that the charge moved? c. What is the magnitude of E? d. What was the change...
Problem 2 A particle with charge +7.60 nC is inside a uniform electric field directed to the left. Another force, in addition to the electric force, acts on the particle so that when it is released from rest, it moves to the right. After it has moved 8.00 cm, the additional force has done 6.50-10-4 J of work and the particle has 4.35-10-5 J of kinetic energy. (a) What work was done by the electric force? (b) What is the...
A particle with a charge of 4.30 nC is in a uniform electric field vec {rm E} directed to the left. It is released from rest and moves to the left; after it hasmoved 8.00 {rm cm}, its kinetic energy is found to be 1.50×10?6 J. What work was done by the electric force? What is the potential of the starting point with respectto the endpoint? What is the magnitude of vector E?
A proton is acted on by an uniform electric field of magnitude 233 N/C pointing in the negative y direction. The particle is initially at rest. (a) In what direction will the charge move? (b) Determine the work done by the electric field when the particle has moved through a distance of 3.35 cm from its initial position. (c) Determine the change in electric potential energy of the charged particle. (d) Determine the speed of the charged particle.
A uniform electric field has magnitude E and is directed in the negative x-direction. The potential difference between point a (at x = 0.60 m) and point b (at x = 0.80 m) is 240 V. (CLO2-PLO2, C2) (a) Which point, a or b, is at the higher potential? (b) Calculate the value of E. (c) A negative point charge q = -0.500 mC is moved from b to a. Calculate the work done on the point charge by the electric field.
A charge moves a distance of 1.8 cm in the direction of a uniform electric field having a magnitude of 249 N/C. The electrical potential energy of the charge decreases by 117.7 × 10−19 J as it moves. Find the magnitude of the charge on the moving particle. The electrical potential energy depends on the distance moved in the direction of the field. Answer in units of C.
A uniform electric field has magnitude E and is directed in the negative i direction. The potential difference between point a (at x= 0.65 m) and point b (at x = 0.90 m) is 260 V.Calculate the value of E. Part C A negative point charge q= -0.200 pC is moved from b to a. Calculate the work done on the point charge by the electric field.
A proton is acted on by an uniform electric field of magnitude 273 N/C pointing in the negative y direction. The particle is initially at rest. (a) In what direction will the charge move? (b) Determine the work done by the electric field when the particle has moved through a distance of 3.25 cm from its initial position. (c) Determine the change in electric potential energy of the charged particle. d) Determine the speed of the charged particle.
A uniform electric field of 9.1 N/C is directed in the -x direction. What is the change in electric potential (not electric potential energy) if moving a distance of 0.25 meters in the -y direction in Volts? If negative, include a negative sign.
A uniform electric field of magnitude 280 V/m is directed in the positive x direction. A +15.0 µC charge moves from the origin to the point (x, y) = (20.0 cm, 50.0 cm). (a) What is the change in the potential energy of the charge field system? J (b) Through what potential difference does the charge move? V