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A charge moves a distance of 1.8 cm in the direction of a uniform electric field...

A charge moves a distance of 1.8 cm in the direction of a uniform electric field having a magnitude of 249 N/C. The electrical potential energy of the charge decreases by 117.7 × 10−19 J as it moves. Find the magnitude of the charge on the moving particle. The electrical potential energy depends on the distance moved in the direction of the field. Answer in units of C.

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Answer #1

The electrical potential energy of the charge is The magnitude of the charge on the moving particle is LU q=Ed=(249)(18x10町 117.7×10-19 = 2.626×10-18 C

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