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When 88.9 g of calcium and 59.8 g of nitrogen gas undergo a reaction that has...

When 88.9 g of calcium and 59.8 g of nitrogen gas undergo a reaction that has a 88.8% yield, what mass of calcium nitride forms?

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Answer #1

Equation: 3Ca + N2> Ca^N2 No of moles of Ca = 88.9 g × = 2.22 mol N° of moles of N2-59.8g×「m-y=214 mol Na No of moles of Ca3N

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