Question

3Ca (s) + N2 (g) ------------> Ca3N2 (s) When 113.2 g of calcium is reacted with nitrogen gas, 64.5 g of calcium nitride is produced. What is the percent yield of the product in this reaction?

Answer 1

3Ca (S) + N2(g) ---------> Ca3N2 (s)

weight of calcium taken = 113.2 g

moles of calcium taken = 113.2/40.08 = 2.82 moles

weight of calcium nitride formed = 64.5 g

molar mass of calcium nitride = 148.25 g/mol

moles of calcium nitride formed = 64.5/148.25 = 0.44 moles

from the reaction 3 moles of calcium should form 1 mole of calcium nitride

so 2.82 mole should form 0.94 mol

so percent yield = 0.44/0.94*100 = 46.8%