Ca3P2(s) + 6H2O(l) = 2PH3(g) + 3Ca(OH)2 How many moles of calcium hydroxide have been produced...

Question

Question

Ca3P2(s) + 6H2O(l) = 2PH3(g) + 3Ca(OH)2 How many moles of calcium hydroxide have been produced when 9.0 moles of calcium phosphide have reacted?

Answer 1

Answer #1

Answer

27moles

Explanation

Ca3P2(s) + 6H2O(l) ------> 2PH3(g) + 3Ca(OH)2

Stoichiometrically, 3moles of Ca(OH)2 is produced from 1mole of Ca3P2

Therefore

number of moles of Ca(OH)2 produced from 9moles of Ca3P2 = 3× 9mol = 27moles

Answer 2

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