Question

Please show work so I can understand the process I would really appreciate it <3

moles of 1. You are given 41 0.0 mL of a 1.581 M KC03 solution. There are K present in the solution. (Fomula) CONCENTRATION MOLES VOLUME 2. You are given 83.5 mL of a 2.101 M solution of AgNOs. If all of the water is allowed to evaporate, then the mass of AgNO3 left in the container is g. 3. If 25.0 ml of a 4.525 M solution of HCI was poured into 112.0 ml of distilled water, the concentration of the resulting solution isM 4. In order to make 250 mL of a 0.100 M HNOs solution from a 15.9 M stock solution, then, ml of the 15.9 M stock HNOs solution is needed. 5. In order to make 500.0 mL of a 1.835 M MgCla solution, then MgClh is needed. g of

Answer 1

All the problems can be solved by using the below relationships (i. e) Molarity equation: Molarity = No. of modes/volume (lit) = weight/mol. Wt times 1000/v (ml) (i. e) Dilution principle c_1 v_1 = c_2 v_2 because c_1 = concentration of first solution v_1 = volume of first solution c_2 = concentration of sound solution v_2 = volume of second solution (1) No. of moles k_2 co_3 = concentration times volume (in lit) = 1.581 times 410/1000 [(i. e) 410 mL = 410/100 lit = 0.648 moles: But, the dissociation of k_2 co_3 can be written as k_2 co_3 2k^(+) + co^-_3 (i. e) 1 mod of k_2 co_3 will gives 2 modes of k^(+) ions Therefore, 0.648 moles of k_2 co_3 will gives 2 times 0.648 = 1.296 moles of k^(+) ions therefore The answer is 1.296 moles of k^(+) ions