Use the reduction potentials and the unbalanced chemical equation below to answer the following questions: Mn2+ (aq) + Ag+ (aq) → Mn (s) + Ag2+ (aq)
Half-cell reaction / E° (V)
Mn2+(aq) + 2e− ⇌ Mn(s) / -1.185
Ag2+(aq) + e− ⇌ Ag+(aq) / 1.980
a) Determine E°cell (in V). Report your answer to three decimal places in standard notation (i.e. 1.234 V)
b) Determine ΔG° (in kJ/mol). Report your answer to three significant figures in scientific notation (i.e. 1.23e4 kJ).
Use the reduction potentials and the unbalanced chemical equation below to answer the following questions: Mn2+...
Use the reduction potentials, the unbalanced half reactions and the unbalanced chemical equation below to answer the following questions: Reaction E° (V) In+(aq) + e− → In(s) -0.140 In3+(aq) + e− → In(s) -0.338 In(s) + In3+(aq) → In+(aq) + In(s) 1. Determine Ecell (in V) for this reaction in the direction shown. Report your answer to three decimal places in standard notation (i.e. 1.234 V). Tries 0/5 2. Determine ΔG° (in kJ) for this reaction. Report your answer to...
Use the following standard cell potentials to answer the questions below. Fe3+(aq) + e− ⇌ Fe2+(aq) E° = 0.771 V Ag3+(aq) + e− ⇌ Ag2+(aq) E° = 1.800 V 1. What is ΔG° (in kJ/mol) for this reaction? Report answer to three significant figures in scientific notation (i.e., 1.23e2 kJ/mol) 2. This reaction is (spontaneous/not spontaneous)
7.An electrochemical cell consists of a Mg electrode in a solution of 0.548 M Mg+ coupled to a Pd electrode in a solution of 0.438 M Pd2+ , all held at 20.1 °C. Mg+(aq) + e− ⇌ Mg(s) E° = -2.700 V Pd2+(aq) + 2e− ⇌ Pd(s) E° = 0.951 V 1. Determine Ecell (in V). Report your answer to three decimal places in standard notation (i.e. 1.234 V). Tries 0/3 2. Determine ΔG (in kJ). Report your answer to three significant...
Standard (reduction) potentials are given below for several half-reactions. Use them to answer the following. Mn2+ (aq) + 2e- → Mn(s) Cr3+(aq) + 3 e- → Cr(s) Sn2+(aq) + 2 e--> Sn(s) Cu2+ (aq) + 2 e → Cu(s) A13+ (aq) + 3 e- → Al(s) Co2+(aq) + 2 e- → Co(s) Cd2+ (aq) + 2 e- → Cd(s) Ered = -1.185 V Ered = -0.744 V Ered = -0.138 V = +0.342 V Ered = -1.662 V Ered =...
What is Eº for the cell Mn| Mn2+ (aq) || Ag+ (aq) | Ag? Standard Reduction Potentials E° (V) Ag+(aq) + e + Ag(s) +0.80 Mn2+(aq) + 2e Mn(s) -1.18 V 1 2 3 Х 1
Ag3+(aq) + e− ⇌ Ag2+(aq)E° = 1.800 V2H+(aq) + 2e− ⇌ H2(g)E° = 0.000 V1. Answer the following questions under standard conditions(a) The half-cell containing Ag2+/Ag3+ is the cathode .(b) The half-cell containing H+/H2 is the anode .(c) What is E°cell (in V)? Report your answer to three decimal places in standard notation (i.e., 0.123 V).1.800 V(b) What is ΔG° (in kJ/mol) for the process that is occurring in the electrochemical cell? Report your answer to three significant figures in...
Use the standard reduction potentials from the following table to choose the weakest reducing agent among those shown below. Ag+(aq) + - + Ag(s) E° = 0.80 V Cu2+(aq) + 2e → Cu(s) E° = 0.34 V Ni2+(aq) + 2e + Ni(s) E° = -0.26 V Cr3+(aq) + 3e- → Cr(s) E° = -0.74 V Mn2+(aq) + 2e → Mn(s) E° = -1.19 V О Ni(s) Ag(s) Cr(s) Mn(s) Cu(s)
please help and answer all questions 4. What is the cell potential for Mn Mn2||Co2|Co, based on the standard potentials? (2 pts) Mn(s) +Co+2 (aq) → Co(s) + Mn+2(aq) 5. A Student constructed a Mg Mg2||Ag|Ag cell and measured a cell potential of 3.17 V. Calculate the cell potential of the Mg Mg2 half reaction. (2 pts) Mg(s) + 2Ag (aq) - 2Ag(s) + Mg(aq) 6. Will silver metal react spontaneously with HCl(aq) to produce H:()? Explain. (2 pts) 2Ag(8)...
Standard (reduction) potentials are given below for several half-reactions. Use them to answer the following. Cd2+ (aq) + 2 e- → Cd(s) Mn2+(aq) + 2 e- → Mn(s) Cu2+ (aq) + 2 e- → Cu(s) Cr3+(aq) + 3 e- → Cr(s) Sn2+(aq) + 2 e- → Sn(s) A13+(aq) + 3 e- → Al(s) Co2+ (aq) + 2 e- → Co(s) Ered = -0.403 V Ered = -1.185 V Ered = +0.342 V Ered = -0.744 V Ered = -0.138 V...
Consider the following half-reactions and their standard reduction potentials then give the standard line (cell) notation for a voltaic cell built on these half reactions. Mn2+(aq) + 2 e- <=> Mn(s) E° = -1.18 V Fe3+(aq) + 3 e- <=> Fe(s) E° = -0.036 V Correct answer: Mn (s) | Mn 2+(aq, 1.0 M) || Fe3+(aq, 1.0 M) | Fe(s) looking for an explanation on how to work this problem, i get confused with the order of the elements. for...