Consider the following half-reactions and their standard reduction potentials then give the standard line (cell) notation for a voltaic cell built on these half reactions.
Mn2+(aq) + 2 e- <=> Mn(s) E° = -1.18 V
Fe3+(aq) + 3 e- <=> Fe(s) E° = -0.036 V
Correct answer: Mn (s) | Mn 2+(aq, 1.0 M) || Fe3+(aq, 1.0 M) | Fe(s)
looking for an explanation on how to work this problem, i get confused with the order of the elements. for example there is another answer that is Mn2+| Mn || Fe| Fe3+ and to me they look similar. how do you determine what goes inside of single line vs the outside?
In an electrochemical cell, an electric potential is created between two dissimilar metals. This potential is a measure of the energy per unit charge which is available from the oxidation/reduction reactions to drive the reaction. It is customary to visualize the cell reaction in terms of two half-reactions, an oxidation half-reaction and a reduction half-reaction.
Reduced species -> oxidized species + ne- |
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Oxidized species + ne- -> reduced species |
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The cell potential (often called the electromotive force or emf) has a contribution from the anode which is a measure of its ability to lose electrons - it will be called its "oxidation potential". The cathode has a contribution based on its ability to gain electeons, its "reduction potential". The cell potential can then be written
Ecell = oxidation potential + reduction potential
If we could tabulate the oxidation and reduction potentials of all available electrodes, then we could predict the cell potentials of voltaic cells created from any pair of electrodes. Actually, tabulating one or the other is sufficient, since the oxidation potential of a half-reaction is the negative of the reduction potential for the reverse of that reaction. Two main hurdles must be overcome to establish such a tabulation
In practice, the first of these hurdles is overcome by measuring the potentials with respect to a standard hydrogen electrode. It is the nature of electric potential that the zero of potential is arbitrary; it is the difference in potential which has practical consequence. Tabulating all electrode potentials with respect to the same standard electrode provides a practical working framework for a wide range of calculations and predictions. The standard hydrogen electrode is assigned a potential of zero volts.
The second hurdle is overcome by choosing standard thermodynamic conditions for the measurement of the potentials. The standard electrode potentials are customarily determined at solute concentrations of 1 Molar, gas pressures of 1 atmosphere, and a standard temperature which is usually 25°C. The standard cell potential is denoted by a degree sign as a superscript.
E°Cell |
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Cell Diagram
The image above is called the cell diagram. This is the standard practice to write the cell diagram. The cell diagram is a representation of the overall reaction in the electrochemical cell. The chemicals involved are what are actually reacting during the reduction and oxidation reactions. (The spectator ions are left out). In the cell diagram, the anode half cell is always written on the left side of the diagram, and in the cathode half cell is always written on the right side of the diagram. Both the anode and cathode are seperated by two vertical lines (ll) as seen in the blue cloud above. The electrodes (yellow circles) of both the anode and cathode solutions are seperated by a single vertical line (l). When there are more chemicals involved in the aqueous solution, they are added to the diagram by adding a comma and then the chemical. For example, in the image above, if copper wasn't being oxidized alone, and another chemical like K was involved, you would denote it as (Cu, K) in the diagram. The cell diagram makes it easier to see what is being oxidized and what is being reduced. These are the reactions that create the cell potential.
the values of standard electrode potential, for reduction to oxidation, move more negative to positive values with lithium most negative to fluorine most positive.
Consider the following half-reactions and their standard reduction potentials then give the standard line (cell) notation...
Consider the following half-reactions and their standard reduction potentials then give the standard line (cel notation for a voltaic cell built on these half reactiors, Mn2+(aq) +26° <=> Mn(s) E° = -1.18V Cr3+(aq) +3 € <=> Cr(s) E° = 0.41 V O A. Cr(s)/C3+(aq, 1.0 M) || Mn2+(aq, 1.0M) | Mn(s) B. Cris) Cr3+(aq, 1.0 M) || Mn (s) | Mn 2+(aq, 1.0 M) OC. Mn (s) | Mn 2+(aq, 1.0 M) || C-3+(aq, 1.0 M) | Cr(s) D. Mn...
pleaae do all, please please please QUESTION 3 Consider the following half-reactions and their standard reduction potentials then give the standard line (cell) notation for a voltaic cell built on these half reactions. Mn2+(aq) + 2 e <-> Mn(s) E = -1.18 V Cr3+ (aq) + 3 e <-> Cris) - 0.41 V A Mn (s) | Mn 2+(aq, 1.0 M) 1 Cr3+(aq. 1.0 M) | Cris) B. Mn (s) Mn 2+(aq, 1.0 M) || Cris) | Cr3+(99, 1.0 M)...
Exercise 18.15 The voltaic cell is represented with the line notation. Standard Reduction Half-Cell Potentials at 25 °C Half Reaction HNO2 (aq) + 2 H+ (aq) + e--+ NO(g) + H20(1) NO. (aq) + 4 H + (aq) + e-? NO(g) + 2 H2O(1) sn't (aq) + 2 e-? Sn2 + (aq) 2H+ (aq) + 2e-?H2(g) Sn2+ (aq) + 2 e-? Sn(s) E (V) 0.98 0.96 0.15 0.00 -0.14
Problem Set #34: Galvanic Cells & Standard Reduction Potential Practice Sheet Directions: (a) Sketch the galvanic cell based on the following overall reaction OR half- reactions. o Show the direction of electron flow o Identify the cathode and anode (b) Give the overall balanced reaction (c) Determine the Evalues for each of the galvanic cells. (d) Give the standard line notation for each cell. (Assume that all concentrations are 1.0M and that all partial pressures are 1.0 atm) 1. 103(aq)...
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