Step 1 of 10: H0: Null Hypothesis: Service calls are equally distributed over the five working days
HA: Alternative Hypothesis: Service calls are not equally distributed over the five working days
Step 2 of 10: The null hpothesis indicates the proportion of service calls received each day is same.
Step 3 of 10: H0: Expected proportions for each category is the same
HA: Expected proportions for each category is not the same
Step 4 of 10: Expected number of service calls on Monday = 80/5=16.00
Step 5 of 10: Expected number of service calls on Wednesday = 16.00
Step 6 of 10:
O E (O - E)2/E
19 16 0.5625
12 16 1
13 16 0.5625
17 16 0.0625
19 16 0.5625
-----------------------------------------------------
= 2.75
Step 7 of 10:
Degrees of freedom = 5 - 1 = 4
Step 8 of 10:
= 0.025
From Table, critical value of = 11.1433
Step 9 of 10:
Since calculated value of = 2.75 is less than critical value of = 11.1433, Fail to reject the null hypothesis at the 0.025 level of significance.
Step 10 of 10:
Conclusion:
The data support the claim that the service calls which they reeive
are equally distributed among the five working days of the
week.
Step 1 of 10 : State the null and alternative hypothesis. Step 2 of 10 :...
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