Question

(CO2) and gaseous water (H20) Suppose Gaseous butane (CH3(CH2),CH3 will react with gaseous oxygen (O2) to produce gaseous carbon dioxide 2.91 q of butane is mixed with 17. g of oxygen. Calculate the minimum mass of butane that could be left over by the chemical reaction. Round your answer to 1s

Answer 1

Step 1: Write the Balanced equation for above Reaction . 2 C?H?? + 13 O? ? 8 CO? + 10 H?O

Step 2: Convert moles Butane to moles CO2 , Convert moles O2 to moles CO2.  

Butane: 2.91 g/ 58.12 g/mole= 0.05 moles Butane, Oxygen: 17 g/ 32 g/mole= 0.53 moles O2

from bal. rxn., 13/2 moles of O? are required for each mole of C?H??. You have 0.05 mol of C?H??, so (0.05)(6.5) = 0.325 mol of O? are required to consume all the butane. therefore butane is limiting reactant because oxygen is 0.53 mole.

Therefore, you have excess oxygen available and so the minimum possible remaining butane is zero, it could all be consumed.

Answer is 0.