thank you Solve the compound inequality. 4y+2> 22 or 3y+36 Write the solution in interval notation....
Question 1 Solve the inequality, write the solution in interval notation. 31 +5 < 11 o(-0,2) 0(-0, 19) O None of these O [2,00) 0 (-0,2) Question 2 Op
Incorrect Your answer is incorrect. Solve the compound inequality. 4u-1>–21 and 3u-5> 7 Write the solution in interval notation. If there is no solution, enter Ø. WIN i 0 - 0 (0,0) 0,0] (0,0) [0.0) 0 DUD X $ ?
9) __ Solve the inequality. Write the solution set in interval notation. 9) - 82 + 6x + 16<0 A) (-0,-8) U (2,0) B) (-0,0) (-2, 8) (8,00) D) (-0,-2)(8.)
Solve the compound inequality and give your answer in interval notation. 12x45 4ax+6>5a 12 OR 3(-6x + 2) + 3 Enter an interval using interval notation (more.)
1.3.17 i Question Help Solve the folowing compound inequality. Write your answer in interval notation or state that there is no solution. 2X _ 5s 7 and 4x + 1-5 Select the correct choice and fill in any answer boxes in your choice below OA. The solution set to the compound inequality is OB. There is no solution. Type your answer in interval notation)
Question 9 Solve the absolute value inequality. Write the solution in interval notation. 243 2 + -197+ 1 @o 21 23 19 19 21] 19 23 19 {-22, 22)
Solve the inequality. Write the solution set in interval notation. 3) 3) (x+ 4)(x+3)x-9)>0
Total Points Possible: 20 2 Solve the inequality -5 <-1 and write the solution using Inequality Notation Preview Graph the solution below: 7 89 10 11 12 13 14 15 16 17 18 19 20 21 22 2 Clear A Line SegmentDotOpen Dot Question 1. Points possible: 2 This is attempt 1 of 1 Solve the following continued inequalities. Use both a line graph and interval notation to write each solution
Solve the inequalities. Write the solution sets in interval notation if possible. a. so b. <0 r2 20 -*2 d. >0
Solve the inequality. Express your answer using set notation or interval notation. Graph the solution set. - 2(4x-5)<2 Choose the correct and per below that is the solution set to the inequality O A. {x[x> 1} or (1,00) OB. {x\x < 1) or (-0,1) O C. {x}x< - 1} or [-00,- 1] OD. {x[x> 1} or [1.00]