HERE
we are given
Vx =15 m/s
Vy =20 m/s
(a)
||v|| = sqrt[(Vx)² + (Vy)²]
||v|| = sqrt[(15 m/s)² + (120m/s)²]
||v|| = 25 m/s
(b)
tanθ = Vy/Vx
θ = arctan(20/15)
θ =53.13°
(c)
90° - 53.13° = 36.87°
A hockey puck is given an initial velocity such that v_x = 15 m/s and v_y...
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