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Please Could Help With Formulas and Explanations: Particles of charge +65, +48, and −95 μCμC are...

Please Could Help With Formulas and Explanations:

Particles of charge +65, +48, and −95 μCμC are placed in a line (Figure 1). The center one is L = 55 cm from each of the others. Calculate the net force on the left charge due to the other two. Enter a positive value if the force is directed to the right and a negative value if the force is directed to the left.

Find:

A) +65 =

B) +48 =

C) -95 =

Thank You

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Answer #1

6546 IN 8h -9846 Lossam cooss m Force on q, due to h (ha) e force on oq duke to qz (713) E = Fiz + This = kaikebla) +149, 2/6که ۹۹ کی 91 * دوہا گو کا +9 + ( - د کرک و) دم ( که و) م د 09 60 ه - - طif you have any queries then give me a comment and give me a like

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