Question

points) Show all work and use the appropriate significant figures question 1. 25 mL of the strong acid perchloric acid is titrated with 0.550 M strong base magnesium hydroxide a) Write out the correct chemical reaction when perchloric acid reacts with magnesium hydroxide. (Hint-Double displacement reaction, Acid + Base give Salt + water) I b) How many grams of perchloric acid are present if it requires 0.3304 L of magnesium hydroxide to reach the endpoint of the titration Foco stv MacBook Air < 3 DOO F4 F5 F6 F7 FB

Answer 1

The answer to this question is simple

A)

The reaction for this titration is

2HClO₄ + Mg(OH)₂ -----> Mg(ClO₄)₂ + 2H₂O

B)

1000 ml 1M solution has 1M

So

0.3304 L of 0.550M will have

0.3304× 0.550

=0.18172 moles

So moles of perchloric acid are double of that

So

Moles = 0.18172 × 2

= 0.36344 moles

And it's mass

= moles × molar mass

= 0.36344 × 100.46

=36.511 gram

I hope this helps if you have any query or want more detailed explanation feel free to ask in the comments section below.