Question

Solve by using moment distribution method 28.904 26.856 16.257 16.257 KN/m 16.257 28.904 KN/m 26.856 KN(m 16-257 KN/m Nm Nm KNIm KNIM B 4.2m C 2.7mG 2.7mI 2.7m 2.7m M O Wh 4.2m 6m 4m E 6 m 6 m 6 un 6 m J A N ITTT

Answer 1

intk is mmetic about mambe given Jovame gstom as we i consfdeajint fixed fixed tnyen in be no monent 8 9oy EN 16-2 6S56k}on TITL Assume stidsnasx Por mombers ie EI = Canstant Sane Fixed end mo ments. 2-49 kN-m Pu MCE - mfeC - 26.s56x y 2. - 35. 81 EN-M -wp2 - G. 257 x Q.7 2. J.8& kN-m 2- -16-2S7x2 2- - EN-m 2 Distuibuhon jactoi. (0-F) mambes D.F JointB BA O 53 4.2 Jointc C D O. 255 C B 0 364 CE 0 302 HHH

C b Tojnt E hrambr eD KE DC Ec EF EG FEGE G GI BA O.41 0.59 0.25 38 2 032 0.21 o.47 G.40-19 0.y 0 361 O 9.8 Fredend mamnt 42.y42-49 35.B 3.06 Balance てhitl 25.07-2.13H.7 -55 83-5.4H2 Caroyeves -2.73 -61 -L29 4.2 -1.22. 2.5 Balan c -6-6842. 2 -S.13-3.16 O.41 0.27 o.G 2.51.12 2.5 0 25 -1.S 0.3 -1061-1.58 O 56 1-3 1.3 の3 to-2 40-1 0.0b 12 -0 -o50-12 Balan ce 0.62 0.89 |-0.21-0-15 -0.22 o.12 -0.06 Comyoven 0.3 -0.040.03 .04 0.02 -0.11 0.y5 0.05 Sabon n.0-0.1-013-019 -0.03-a.0 O-03 .05 -2 Hn-o|-20|-256 65(.06 |5.1 1.21 9.27 Fromas -ive = clAckwi se -ire =» Anticdockuie

So45.07 753 65 4.2m 0.59 1 So 4 wŁ .06 urch 6m 6m rhom L N S.27 TL