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QUESTION 4 1 points Using Newton's revision of Kepler's third law, calculate the mass (in solar...
Now M is the sum of the two masses in units of the solar mass .e. the mass of our Sun), while a is still in AU and P in years. An important application of Newton's generalization of Kepler's third law is being able to dete mine mass of a central body based on the motion of a satellite around that body. If the satellite is much less massive than the body it's orbiting, then M is essentially equal to...
In Lecture 4, we discussed Kepler’s third law relatingthe orbital period of a planet (p) to the semi-major axis (orbital distance, a) of its orbit(p2= a3). We can apply this law as long the object orbits the Sun or another object of the same mass, and the units of orbital period are in (Earth) years and the orbital distance is in Astronomical Units(AU). [1AU is equal to the distance between the Earth and the Sun]. [Note: Newton extended this law...
6. Using Nowton's version of Kepler's Third Law (15 points). a) (5pt) Compute the semimajor the mass of the Sun from the fact that the Earth's orbital period is 1 year and axis is 1 AU. Assume that the mass of the Earth is much smaller than the mass of the Sun. Is this assumption justified? pt) Compute the orbital period of a cubesat orbiting the Earth at an altitude of 400 km above the Earth's surface. c) (5pt) Estimate...
According to Kepler's third law, there is a relation between the period of one revolution for the satellite, the semimajor axis length of the Moon, and its mass. By applying this law, find the Moon's mass, in Kg, while the orbital period of this motion is 50,000 s and the semi-major axis of the Moon is equal to 5 m. (Round your answer to the nearest whole number)
Newton's version of Kepler's Law Force Example Use what we know about the earth's orbit to estimate the mass of the sun. For this problem we can use Newton's form of Kepler's law Solving for the sum of the masses we get to use this law we need all our values to be kilograms, meters, and seconds. a 1AU-149.6x10P m and p- 1 year (365.25 days/year)(24 hours/day)(3600 seconds/hour)-3.15x 10" sec. Placing these values in to our equation we get M+...
Derive Kepler's 2^nd law from conservation of angular momentum Derive Kepler's 3^rd law from Newton's laws of motion and gravitation for a circular tool You have landed a job with Space X as a space physicist. Your first job is to launch a satellite. The plan is to lift off from the surface of the Earth and then insert the satellite into an elliptical transfer orbit with its perigee at A and apogee at A'. The spacecraft will be unpowered...
Kepler’s Third Law indicates that the Period (P) of an orbit is related to the semi-major axis (a) of the orbit with: P 2 = ka3 . Kepler noticed that the value of the constant k changes when we observe systems with different central objects. This means that the orbits of all of the planets in the Solar System have the same value for k, but that value is different for the Moon because all of the planets orbit the...
Question 6 (8 points) A spherical planet has 12 times the earth's mass and has three times the earth's radius. It orbits a star with 5 times the sun's mass with an orbital period of 7 years. What is the orbital radius of this planet in AU, where 1 AU is the earth-sun distance
Question 7 (0.5 points) What causes the Moon to move about 12° across the sky from one night to the next (at the same time of night, of course)? O Because the Earth is turning on its axis. O Because the Moon is moving in its orbit. The Sun has also moved 15° across the sky and gravitationally pulls the Moon with it. The celestial sphere the Moon is attached to has moved 15°. O It is an optical illusion....
3. In this problem, we are going to examine the supermassive black hole in the center of our galaxy, Sagittarius A.. (a) (15 points) We can calculate its mass using the orbits of stars gravitationally bound to it in the same way that you can use the Earth's orbit to calculate the mass of the Sun). The orbit of a star, S2, has been fully mapped out. Its period is 15.24 yr and semi-major axis length is 980 AU. Using...