Translate these loops into C. Assume that the C level integer i is held in register $t1,$s2 holds the c level integer called result, and $s0 holds the base address of the integer MemArray.
addi $t1, $s0, 400
loop: lw $s1, 0($s0)
add $s2, $s2, $s1
lw $s1, 4($s0)
add $s2, $s2, $s1
addi $s0, $s0, 8
bne $t1, $s0, Loop
addi $t1, $s0, 400 # $t1 = &MemArray[100] loop: lw $s1, 0($s0) # $s1 = MemArray[0] add $s2, $s2, $s1 # result = result + MemArray[0] lw $s1, 4($s0) # $s1 = MemArray[1] add $s2, $s2, $s1 # result = result + MemArray[1] addi $s0, $s0, 8 # MemArray += 2 bne $t1, $s0, Loop # C code: -------- int i = 0; while (i < 100) { result += MemArray[i] + MemArray[i+1]; i += 2; }
Translate these loops into C. Assume that the C level integer i is held in register...
2. The table below holds MIPS assembly code fragments with different branch instructions LOOP addi $s2. $s2. 2 subi $t1. st1. 1 bne t1. 0. LOOP DONE: LOOP: it st2. $0. stl beq t2. 0. DONE addi $s2. Ss2. 2 LOOP DONE: For the loops written in MIPS assembly in the above table, assume that the register Şt1 is initialized to the value of 10. What is the value in register $s2 assuming that $s2 initially has a value of...
2.29 The following is the C codes and the translated MIPS codes. Assume that the C-level integers t1 and a0 are held in register $t1 and $a0, and $s0 holds the base address of the integer MemArray. void foo () { int MemArray[100] = { 96, 98, 63, 69, 42, 27, 16, 6, 47, 74, 44, 33, 76, 7, 88, 33, 80, 86, 86, 64, 17, 67, 60, 51, 2, 61, 93, 87, 49, 98, 24, 98, 30, 65, 2,...
Using beq only, not bge! Translate the following C code to MIPS assembly code. Use a minimum number of instructions. Assume that the values of a, b, i, and j are in registers $s0, $s1, $t0, and $t1, respectively. Also, assume that register $s2 holds the base address of the integer array D. Comments are required. for(i=1; i<a; i++) for(j=1; j<b; j++) D[2*j] = i + j;
im trying to complete mips program code about a calculator program that can calculate integer addition / subtraction written using the MIPS assembler. im having hard times to debug this. The input is given to the array of Formula char (base address $ s0) in the form of a formula. The null character (\ 0, ASCII code 0) is placed at the end. The calculation result is given to the register $ s1 and the overflow is ignored. For example,...
Please do the following problems 1. translate into RISC-V Assembly variable rpt in x19 register. if(rpt>0){ rpt=rpt-1; goto loop } 2. Translate the following Risc-V code into C. variable 'i' in register x5, variable 'result' in x6 ,base address of integer 'memarray' in x10 addi x6,x0,0 addi x29,x0,100 LOOP: ld x7,0(x10) add x5,x5,x7 addi x10,x10,8 addi x6,x6,1 blt x6,x29, LOOP
Translate the following C code to MIPS assembly. Assume that the values of a, b, i, and j are in registers $s0, $s1, $t0, and $t1, respectively. Also assume that $s2 holds the base address of the array D. for (i = 0: i < a: i++) for (j = 0: j < b: j++) D[2 * j] = i + j;
Translate the following C code to MIPS assembly code. Assume that the value of i is in register $t0, and $s0 holds the base address of the integer MemArray if (i > 10) MemArray[i] = 0; else MemArray[i] = -MemArray[i];
Assignment 3 Translate the following MIPS code to C. Assume that the variables f, g, h, i and j are assigned to registers Ss0, Ss1, Ss2, Ss3 and Ss4, respectively. Assume that the base address of the arrays A and B are in registers Ss6 and $s7, respectively. addi St0, Ss6, 4 add $t1, $s6, $0 #register $0 always holds 320s sw St1, 0(Sto) add Ss0, St1, Sto
I AM POSTING MY QUESTION 3RD TIME . FIRST TWO TIMES I DIDNOT GET THE PROPER ANSWER. PLEASE DO ALL STEPS BY LABELING THE EACH STEP. THIS IS THE ASSIGNMENT IN WHICH THE EACH STEP SHOULD BE LABEL . I MEAN EVERY THING SHOULD BE WRITTEN WHAT WE HAVE DONE IN OUR PROGRAM THIS IS THE REQUIREMENT OF TEACHER , PLEASE DO IT PROPERLY 1) MIPS to C. Assume that the variables f, g, h, i, and j are assigned...
WRITE THE FOLLOWING CODE IN FLOATING POINT NUMBERS IN ASSEMBLY LANGUAGE USING MIPS IN MARS .data prompt: .asciiz "\nMaximum number is : " prompt1: .asciiz "\nMinimum number is : " prompt2: .asciiz "\nRange of the array is : " size: .word 10 #load array array: .word 23, -12, 45, -32, 52, -72, 8, 13,22,876 .text #load address of array and size la $s4,array #load address of A lw $t0,size #load i to t0 jal getArrayRange li $v0, 4 la...