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amswer ASAP
Please
ue sua Electric Charge Electric Force Electric Field A positive charge of 50 microCoulombs is located along the positive adsy
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Solution A besuc E 여 Im B 0 2.1m Im E, DJ+SMC is. A The hypotenuse AB A B = 12+ (2.1)2 B 2.1 3 AB 5 5.41 Now electric field d= B can by adding the Let E E = E. Now net electric field at x = 2.1 m be calculated no & yo components of È & E. that compon

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