Solution
Given that,
Using standard normal table
a ) P ( Z > 1.02 )
1 - P ( Z < 1.02 )
= 1 - 0.8461
= 0.1539
Probability = 0.1539
b ) P ( Z - 2.36 )
= 0.0091
Probability = 0.0091
c ) P ( 0 Z 1.64 )
P ( Z 1.64 ) - P ( Z 0 )
= 0.9495 - 0.5000
= 0.4495
Probability = 0.4495
d ) P ( -0.82 Z 2.54 )
P ( Z 2.54 ) - P ( Z -0.82 )
= 0.9945 - 0.2061
= 0.7884
Probability = 0.7884
mbi Saved Exercise 6-15 Algo Find the following probabilities based on the standard normal variable Z....
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