Find the following probabilities based on the standard normal variable Z. (You may find it useful to reference the z table. Leave no cells blank - be certain to enter "0" wherever required. Round your answers to 4 decimal places.)
Solution :
Given that ,
a)P( -1.03 z -0.62 )
= P(z -0.62) - P(z -1.03)
=0.2676 - 0.1515 = 0.1161
probability = 0.1161
b)
P( 0.04 z 2.13 )
= P(z 2.13) - P(z 0.04)
=0.9834 - 0.5160 = 0.4675
probability = 0.4675
c)
P( -1.42 z 0.07)
= P(z 0.07) - P(z -1.42)
=0.5279 - 0.0778 = 0.4501
probability = 0.4501
d)p(z >3)
= 1-p(z< 3)
= 1-0.9987 = 0.0013
probability = 0.0013
Find the following probabilities based on the standard normal variable Z. (You may find it useful...
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