Solution:
Using Standard Normal Table(Z table)
a.)P(0< Z< 2.58)=P(Z<2.58 )- P(Z< 0)=0.9951-0.5000=0.4951
b.)P(0< Z< 1)=P(Z<1 )- P(Z< 0)=0.8413-0.5000=0.3413
c.)P(-2.10< Z< 0)=P(Z<0 )- P(Z< -2.10)=0.5000-0.0179=0.4821
d.)P(-2.10< Z< 2.10)=P(Z< 2.10 )- P(Z< -2.10)=0.9821-0.0179=0.9642
e.)P(Z< 1.32)=0.9066
f.)P(Z> -1.55)=1-P(Z< -1.55)=1-0.0606=0.9394
g.)P(-1.10< Z< 2.00)=P(Z< 2.00 )- P(Z< -1.10)=0.9772-0.1357=0.8415
h.)P(1.32< Z< 2.50)=P(Z< 2.50 )- P(Z< 1.32)=0.9938-0.9066=0.0872
i)P(Z> 1.10)=1-P(Z< 1.10)=1-0.8643=0.1357
j.)P(|Z|<2.50)=P(-2.50< Z< 2.50)=P(Z< 2.50 )- P(Z< -2.50)=0.9938-0.0062=0.9876
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