significent @ Use the given values of n and p to find the minimum related binomial...

Question

Question

Answer 1

Answer #1

n = 94 and p = 0.24

mean = np = 94*0.24 = 22.5600
std. dev. = sqrt(94*0.24*0.76) = 4.1407

minimum value = mu - 2*sigma = 22.56 - 2*4.1407 = 14.2786
maximum value = mu + 2*sigma = 22.56 + 2*4.1407 = 30.8414

b)

35 is not part of the above CI, hence 35 is significant

Answer 2

Similar Homework Help Questions

Use the given values of n and p to find the minimum usual value μ -...

Use the given values of n and p to find the minimum usual value μ - 2σ and the maximum usual value μ + 2σ. Round your answer to the nearest hundredth unless otherwise noted. n = 166, p = 0.15
Use the given values of n and p to find the minimum usual value µ -...

Use the given values of n and p to find the minimum usual value µ - 2σ and the maximum usual value µ + 2σ. n = 1130, p = 0.94 Group of answer choices Minimum: 1050.91; maximum: 1073.49 Minimum: 1046.23; maximum: 1078.17 Minimum: 1054.22; maximum: 1070.18 Minimum: 1078.17; maximum: 1046.23
(l point) 14. Use the given values ofn and p to find the minimum usual value...

(l point) 14. Use the given values ofn and p to find the minimum usual value u - 2o and the maximum usual value u +2o. Round your answer to the nearest hundredth unless otherwise noted. n 261,p OMinimum: 65.12; maximum: 39.28 OMinimum: 39.28; maximum: 65.12 OMinimum: 45.74; maximum: 58.66 OMinimum: 43.06; maximum: 61.34 (I point) 15. Find the standard deviation, a, for the binomial distribution which has the stated values ofn and p. Round your answer to the nearest...

Assume that a procedure yields a binomial distribution with n trials and the probability of success...

Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean mu μ and standard deviation sigma σ. Also, use the range rule of thumb to find the minimum usual value mu minus 2 sigmas μ−2σ and the maximum usual value mu plus 2 sigma μ+2σ. n equals = 250 , p equals = 0.75 mu μ equals...
Assume that a procedure yields a binomial distribution with n trials and the probability of success...

Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean μ and standard deviation σ. Also, use the range rule of thumb to find the minimum usual value μ_2ơ and the maximum usual value μ+ 2σ. n 1465, p 2/5 586 (Do not round.) σ-| | (Round to one decimal place as needed.)
Assume that a procedure yields a binomial distribution with n trials and the probability of success...

Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean μ and standard deviation σ. Also, use the range rule of thumb to find the minimum usual value μ−2σand the maximum usual value μ+2σ. n=1475, p=3/5

8). Assume that a procedure yields a binomial distribution with n trials and the probability of...

8). Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean and the standard deviation. Also, use the range rule of thumb to find the minimum usual value and the maximun usual value. (n = 130, p = 0.6) μ =____ (Do not round.) σ =_____ (Round to one decimal place as needed.) μ−2σ = _____ (Round...
Assume that a procedure yields a binomial distribution with n trials and the probability of success...

Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. n= 1575, p= 2/5 Use the range rule of thumb to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. μ = _____ σ = _____ μ−2σ = _____ μ+2σ = _____
Find the mean for the binomial distribution which has the stated values of n and p....

Find the mean μ for the binomial distribution which has the stated values of n and p. Round answer to the nearest n=676, p=0.7 A μ=471.7 B μ=474.9 C. μ=474.5 D. μ=473.2